Squares of numbers ending with 5
This method of finding the square of a number ending with five is based on the Sutra of " Ekadhikena Purvena " of respectable Vedas . It means "one more than the one before it " or " one more than the previous one .
Explaining the method by an example : -
Example 1 : - Find the square of 95 .
i.e.
9 * (9 + 1) = 9 * 10 = 90
Step 2 : -
Now we place 25 next to the digit obtained above .
i.e.
9025
which gives us the answer.
Step 1 : -
5 * (5 + 1) = 5 * 6 = 30
12 * ( 12 + 1) = 12 * 13 = 156
Step 2 : -
Place 25 next to it .
Answer is 15625 .
Explaining the method by an example : -
Example 1 : - Find the square of 95 .
Answer : -
Step 1 : -
In this we simply make the square by simply multipling the digit(s) previous to 5 by one more than themselves . i.e.
9 * (9 + 1) = 9 * 10 = 90
Step 2 : -
Now we place 25 next to the digit obtained above .
i.e.
9025
which gives us the answer.
=>Answer is 9025.
Example 2 : - Find the square of 55.Answer : -
Proceeding as above :Step 1 : -
5 * (5 + 1) = 5 * 6 = 30
Step 2 : -
Place 25 next to it . Answer is 3025.
Note : - We can extend the rule to any number of digits .
Example 3 : - Find the square of 125 .Answer : -
Step 1 : -12 * ( 12 + 1) = 12 * 13 = 156
Step 2 : -
Place 25 next to it .
Answer is 15625 .
Algebraic proof : -
Consider the expantion
(a.x + b )2 = a2.x2 + 2a.x.b + b2
Substituting x = 10 and b = 5
(10.a + 5)2 = 102.a2 + 2.10.a.5 + 52
= 100.a2 + 100.a + 25
= (a2 + a)100 + 25
= a.(a + 1)102 + 25
In the above a.(a + 1).100 gives a.(a + 1)/00 and + 25 gives
a.(a + 1)/25 .
which is our answer
(a.x + b )2 = a2.x2 + 2a.x.b + b2
Substituting x = 10 and b = 5
(10.a + 5)2 = 102.a2 + 2.10.a.5 + 52
= 100.a2 + 100.a + 25
= (a2 + a)100 + 25
= a.(a + 1)102 + 25
In the above a.(a + 1).100 gives a.(a + 1)/00 and + 25 gives
a.(a + 1)/25 .
which is our answer
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